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![Show that each conditional statement is a tautology without using truth tables. a) [\neg pwedge (pv q)]to q b) [(p to q)wedge (qto r)]to (pto r) c) [pwedge (pto q)] to q d) [(](https://homework.study.com/cimages/multimages/16/taut_b7057744632800433890.png "Show that each conditional statement is a tautology without using truth tables. a) [\neg pwedge (pv q)]to q b) [(p to q)wedge (qto r)]to (pto r) c) [pwedge (pto q)] to q d) [(")
Show that each conditional statement is a tautology without using truth tables. a) [\neg pwedge (pv q)]to q b) [(p to q)wedge (qto r)]to (pto r) c) [pwedge (pto q)] to q d) [(
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